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A car travelling at 40 km/h stops in a distance of 10m when brakes are applied. If the car was travelling at 80 km/h. What would be the stopping distance. |
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Answer» u1 = 40 km/h s1 = 10 m u2 = 80 km/h s2 = ? Stopiing distance s = u2/2a \(\frac{s_2}{s_1}=(\frac{u_2}{u_1})^2\) s2 = s1\((\frac{u_2}{u_1})^2\) = 10 \((\frac{80}{40})^2\) s2 = 40 M |
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