A car starts with an acceleration of 2m/s2 and it accelerates for 5 seconds and for another 5 seconds it runs with constant velocity and then deaccelerates with 2m/s and finally comes into rest. Find 1.Total distance travelled 2.Average velocity

A car starts with an acceleration of 2m/s2 and it accelerates for 5 se

1.	A car starts with an acceleration of 2m/s2 and it accelerates for 5 seconds and for another 5 seconds it runs with constant velocity and then deaccelerates with 2m/s and finally comes into rest. Find 1.Total distance travelled 2.Average velocity
Answer» u = 0 a = 2m/s² t = 5s S = ut+½at² = 25m v =u+at =0+25 = 10m/s Now, speed = 10m/s Time = 5s Therefore, DISTANCE= st =105 = 50m Again, acceleration=-2m/s² u =10m/s v = 0 Therefore,time = v-u/a = 0-10/-2 = 5 s and, s= v²-u²/2a = -100/2(-2) = 25m 1. TOTAL distance =25+50+25 =100m 2. Avg. Velocity = Total distance/total time = 100/5+5+5 = 100/15 = 6.66m/s

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A car starts with an acceleration of 2m/s2 and it accelerates for 5 seconds and for another 5 seconds it runs with constant velocity and then deaccelerates with 2m/s and finally comes into rest. Find 1.Total distance travelled 2.Average velocity

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