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A car starts moving with an acceleration 5 m/s for 10 sec then it decelerates with 2m/s find the total distance travelled by the car till it stop |
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Answer» Answer: The TOTAL DISTANCE traveled= 625+250 =875m Explanation: LET us first calculate the velocity ACHIEVED by the car at the end of 10s v=u+at as u=0 v=50m/s distance traveled at the end of first 10 sec= s= at²÷2= 5×100÷2= 250m Time TAKEN for the car to go to rest that is v=0, u=50 a=-2 v=u+at t=u÷a=25s Distance travelled= 2×a×s =v²-u² 2×2×s=2500 s=2500÷4 s=625 The total distance traveled= 625+250 =875m |
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