A car starts from rest and moves along the x-axis with constant acceleration 5 ms2 for 8 seconds. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from rest?

A car starts from rest and moves along the x-axis with constant acce

1.	A car starts from rest and moves along the x-axis with constant acceleration 5 ms2 for 8 seconds. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from rest?
Answer» 480M Explanation:Given :- acceleration (a) = 5m/s² time = 8sec u (initial velocity) =0 We KNOW , V = u + at v = 0+ 5* 8 v = 40m/s Now according to question at same velocity v = 40m/s in time 12sec . what will be distance So, we know that , velocity = DISPLACEMENT/time 40 = displacement / 12 displacement = 40*12 distance/displacement = 480m Answer ________________________________Hope it's helpful

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A car starts from rest and moves along the x-axis with constant acceleration 5 ms2 for 8 seconds. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from rest?

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