A car starts from rest and again comes to rest after trav- elling a distance of 12 km in 1/8 hour. Its maximum velocity in between is 120km/h. In its journey, accelera-tion and retardation are both uniform, and the value ofacceleration is half that of retardation. How long doesthe car travel with uniform velocity?ans is [4.5 min).please solve in correct way don't give wrong answer.

A car starts from rest and again comes to rest after trav- elling a

1.	A car starts from rest and again comes to rest after trav- elling a distance of 12 km in 1/8 hour. Its maximum velocity in between is 120km/h. In its journey, accelera-tion and retardation are both uniform, and the value ofacceleration is half that of retardation. How long doesthe car travel with uniform velocity?ans is [4.5 min).please solve in correct way don't give wrong answer.
Answer» Okay, let's write the given data.Acceleration (α) = ½ Retardation (β) [α=½β OR 2α=β] ----- (1)Distance (s) = 12 Km ⇒ 12000 m [Convert Km into m] Maximum velocity (v₁) = 120 Km⁻¹ ⇒ (100/3)ms⁻¹ Time (t₁) = 1/8th of an hour ⇒ 7.5 minutes.Time of car TRAVEL (t₂)initial velocity (u) = 0Final velocity (v) = 0THEN, use this FORMULA:v₁ =αt₁ =(β+α )÷(αβt₂ )HOPE THIS HELPS :D

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