A car starts from rest and accelerates uniformly over a time of 5.2 se

1.	A car starts from rest and accelerates uniformly over a time of 5.2 sec for a distance of 110 m Determine the acceleration of the car
Answer» Answer: <U>a = 8.136 m/s² Explanation: t = 5.2 seconds S = 110 m (Initial velocity) u = 0 m/s By the SECOND law of MOTION = S = UT + 1/2at² 110 = 0(5.2) + 1/2 * a (5.2)² 110 = 0 + 13.52 a 110 = 13.52 * a a = 110 / 13.52 a = 8.136 m/s²

A car starts from rest and accelerates uniformly over a time of 5.2 sec for a distance of 110 m Determine the acceleration of the car

Answer»

Answer:

<U>a = 8.136 m/s²

Explanation:

t = 5.2 seconds

S = 110 m

(Initial velocity) u = 0 m/s

By the SECOND law of MOTION = S = UT + 1/2at²

110 = 0(5.2) + 1/2 * a *(5.2)²

110 = 0 + 13.52 * a

110 = 13.52 * a

a = 110 / 13.52

a = 8.136 m/s²

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A car starts from rest and accelerates uniformly over a time of 5.2 sec for a distance of 110 m Determine the acceleration of the car​