A car starting from rest atains avelocity of 60 km/h in 10 min. Calcul

1.	A car starting from rest atains avelocity of 60 km/h in 10 min. Calculate the acceleration and distance traveled by The care, assuming that acceleration is uniform
Answer» $\large\frak{given} \begin {cases} \: \sf initial \: velocity (u)= \frak{0} km/hr \\ \sf \: final \: velocity(v) = \frak{60}km/hr \\ \sf \: time(t) = \frak{10 \: min = \red{\dfrac{1}{6} hr}}\end{cases}$ Intial Velocity is 0km/hr because the vehicle is starting from the REST. We are provided with above information from the question and we are asked to find the acceleration of this car and distance traveled by this car. So, First we have to CALCULATE the value of acceleration by using 1ST equation of motion. $: \implies \underline{ \boxed { \pink{{\frak{v = u + at}}}}}$ $\: \: \: \: \: \: \: \dag \: \underline \frak{substituting \: the \: given \: values \: in \: the \: equation : - }$ $\: \: \: \: \: \: \: : \implies \bf \: 60 = 0 + a \bigg(\dfrac{1}{6} \bigg)$ $\: \: \: \: \: \: \: : \implies \bf 60 = \dfrac{a}{6}$ $\: \: \: \: \: \: \: : \implies \bf a = 6 \times 60$ $\: \: \: \: \: \: \: : \implies {\boxed{ \pink{\frak{a = 360 m/ {s}^{2} }}}} \bigstar$ Now, we are going to find the distance traveled by this car with the help of 3rd equation of motion. you can USE 2nd equation as well... there will be no change in the answer but for the sake of my simplicity I'm using 3rd equation :) $: \implies \underline{ \boxed { \pink{{\frak{v²=u²+2as}}}}}$ the letter "s" introduced in this equation represents "distance traveled by the body" $\: \: \: \: \: \: \: \dag \: \underline \frak{substituting \: the \: given \: values \: in \: the \: equation : - }$ $\: \: \: \: \: \: \: : \implies \bf \: {(60)}^{2} = {(0)}^{2} + 2(360)s$ $\: \: \: \: \: \: \: : \implies \bf \: 3600 = 0 + 720s$ $\: \: \: \: \: \: \: : \implies \bf \: s = \cancel\dfrac{3600}{720}$ $\: \: \: \: \: \: \: : \implies {\boxed{ \pink{\frak{s = 5 \: m }}}} \bigstar$ $\therefore {\underline{ \sf {our \: respective \: answers \: are \: 360m {s}^{ - 2} \: and \: 5 \: m}}}$ i hope it's beneficial :D

A car starting from rest atains avelocity of 60 km/h in 10 min. Calculate the acceleration and distance traveled by The care, assuming that acceleration is uniform

Answer»

$\large\frak{given} \begin {cases} \: \sf initial \: velocity (u)= \frak{0} km/hr \\ \sf \: final \: velocity(v) = \frak{60}km/hr \\ \sf \: time(t) = \frak{10 \: min = \red{\dfrac{1}{6} hr}}\end{cases}$

Intial Velocity is 0km/hr because the vehicle is starting from the REST.
We are provided with above information from the question and we are asked to find the acceleration of this car and distance traveled by this car.
So, First we have to CALCULATE the value of acceleration by using 1ST equation of motion.

$: \implies \underline{ \boxed { \pink{{\frak{v = u + at}}}}}$

$\: \: \: \: \: \: \: \dag \: \underline \frak{substituting \: the \: given \: values \: in \: the \: equation : - }$

$\: \: \: \: \: \: \: : \implies \bf \: 60 = 0 + a \bigg(\dfrac{1}{6} \bigg)$

$\: \: \: \: \: \: \: : \implies \bf 60 = \dfrac{a}{6}$

$\: \: \: \: \: \: \: : \implies \bf a = 6 \times 60$

$\: \: \: \: \: \: \: : \implies {\boxed{ \pink{\frak{a = 360 m/ {s}^{2} }}}} \bigstar$

Now, we are going to find the distance traveled by this car with the help of 3rd equation of motion.
you can USE 2nd equation as well... there will be no change in the answer but for the sake of my simplicity I'm using 3rd equation :)

$: \implies \underline{ \boxed { \pink{{\frak{v²=u²+2as}}}}}$

the letter "s" introduced in this equation represents "distance traveled by the body"

$\: \: \: \: \: \: \: \dag \: \underline \frak{substituting \: the \: given \: values \: in \: the \: equation : - }$

$\: \: \: \: \: \: \: : \implies \bf \: {(60)}^{2} = {(0)}^{2} + 2(360)s$

$\: \: \: \: \: \: \: : \implies \bf \: 3600 = 0 + 720s$

$\: \: \: \: \: \: \: : \implies \bf \: s = \cancel\dfrac{3600}{720}$

$\: \: \: \: \: \: \: : \implies {\boxed{ \pink{\frak{s = 5 \: m }}}} \bigstar$

$\therefore {\underline{ \sf {our \: respective \: answers \: are \: 360m {s}^{ - 2} \: and \: 5 \: m}}}$

i hope it's beneficial :D

A car starting from rest atains avelocity of 60 km/h in 10 min. Calculate the acceleration and distance traveled by The care, assuming that acceleration is uniform

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A car starting from rest atains avelocity of 60 km/h in 10 min. Calculate the acceleration and distance traveled by The care, assuming that acceleration is uniform​

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A car starting from rest atains avelocity of 60 km/h in 10 min. Calculate the acceleration and distance traveled by The care, assuming that acceleration is uniform