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a car starting from rest acquires a speed 25 m/s in 10 sec.after which it maintains this speed for 10 sec. find(a) the acceleration (b) distance travelled during acceleration (c) total distance travelled? |
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Answer» u = 0 m/s V = 25 m/s t = 10 m/s a) a = ? As v = u + a t so, 25 = 0 + a * 10 so, a = 25/10 = 2.5 m/s^2 b) s = ? (for FIRST 10 s) As s = ut + 1/2 a t^2 so, s = 0 + 1/2 * 2.5 * 10^2 so. s = 125 m c) s = ? ( for next 10 s) s = v * t as a = 0 m/s^2 so, s = 25*10 so, s = 250 m Hnce, TOTAL DISTNCE = 125 + 250 = 375 m |
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