1.

a car starting from rest acquires a speed 25 m/s in 10 sec.after which it maintains this speed for 10 sec. find(a) the acceleration (b) distance travelled during acceleration (c) total distance travelled?

Answer»

u = 0 m/s


V = 25 m/s


t = 10 m/s


a) a = ?


As v = u + a t


so, 25 = 0 + a * 10


so, a = 25/10 = 2.5 m/s^2


b) s = ? (for FIRST 10 s)


As s = ut + 1/2 a t^2


so, s = 0 + 1/2 * 2.5 * 10^2


so. s = 125 m


c) s = ? ( for next 10 s)


s = v * t as a = 0 m/s^2


so, s = 25*10


so, s = 250 m


Hnce, TOTAL DISTNCE = 125 + 250


= 375 m



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