A car start from rest and attain a velocity of 20 m/s in 5 s. Calculat

1.	A car start from rest and attain a velocity of 20 m/s in 5 s. Calculate the distance during the time
Answer» car traveled 50 m while ACCELERATING from 0 to 20 m/s in 5 seconds. The distance d is from d = v(avg) • t where v(avg) is the average velocity during the TIME, or v(avg) = v(INITIAL) + ∆v/2. Here v(initial) is 0 and ∆v is 20 m/s, so v(avg) = 20 m/s / 2 = 10 m/s. d = 10 m/s • 5 s = 50 m.

A car start from rest and attain a velocity of 20 m/s in 5 s. Calculate the distance during the time

Answer»

car traveled 50 m while ACCELERATING from 0 to 20 m/s in 5 seconds.

The distance d is from

d = v(avg) • t

where v(avg) is the average velocity during the TIME, or

v(avg) = v(INITIAL) + ∆v/2.

Here v(initial) is 0 and ∆v is 20 m/s, so

v(avg) = 20 m/s / 2 = 10 m/s.

d = 10 m/s • 5 s = 50 m.

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A car start from rest and attain a velocity of 20 m/s in 5 s. Calculate the distance during the time​

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A car start from rest and attain a velocity of 20 m/s in 5 s. Calculate the distance during the time