a car posses avg velocities of 5ms,10ms,15ms in first , second, third seconds wt is the total distanceby the car covered by the car in these 3 seconds

a car posses avg velocities of 5ms,10ms,15ms in first , second, third

1.	a car posses avg velocities of 5ms,10ms,15ms in first , second, third seconds wt is the total distanceby the car covered by the car in these 3 seconds
Answer» 30 m Taking the case of constant acceleration in parts with constant average VELOCITY gives the same answer. So the distance travelled in 1st second = 5 m Distance travelled in 2nd second = 10 m Distance covered in 3rd second = 15 m Which makes the total distance travelled = 5m + 10M + 15m = 30 m.

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a car posses avg velocities of 5ms,10ms,15ms in first , second, third seconds wt is the total distanceby the car covered by the car in these 3 seconds

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