A car of mass 2500 kg moving with a velocity 10 m / sec brought to res

1.	A car of mass 2500 kg moving with a velocity 10 m / sec brought to rest in 5 sec by applying brakes.Find the retarding force produced by the brakes.
Answer» Answer:- Given:- Initial velocity (u) = 10 m/s Final velocity (V) = 0 m/s [Since it will COME on rest] Mass (m) = 2500 kg Time taken (t) = 5 s To Find:- Regarding force (F) produced by the brakes. _____________... FINDING acceleration:- We know, a = (v-u)/t or, a = -u/t where, a = Acceleration, v = Final velocity, u = Initial velocity & t = Time. So, a = - (10 m/s)/5s ➵ a = (-10 m/s)/5s ➵ a = -2 m/s² ...(Acceleration) Finding RETARDATION force:- We know, F = ma where, F = Force, m = Mass & a = Acceleration. ∴ F = (2500 kg) (-2 m/s²) ➵ F = - 5000 kg m s^-2 ➵ F = - 5000 N ...(Force against MOTION) Therefore, the retarding force was (-5000 N) against the path of motion.

A car of mass 2500 kg moving with a velocity 10 m / sec brought to rest in 5 sec by applying brakes.Find the retarding force produced by the brakes.

Answer»

Answer:-

Given:-

To Find:-

Regarding force (F) produced by the brakes.

_____________...

FINDING acceleration:-

We know,

a = (v-u)/t

or, a = -u/t

where,

So,

a = - (10 m/s)/5s

➵ a = (-10 m/s)/5s

➵ a = -2 m/s² ...(Acceleration)

Finding RETARDATION force:-

We know,

F = ma

where,

∴ F = (2500 kg) (-2 m/s²)

➵ F = - 5000 kg m s^-2

➵ F = - 5000 N ...(Force against MOTION)

Therefore, the retarding force was (-5000 N) against the path of motion.