1.

A car moving at a speed of 8.0 m/s merges onto the highway and accelerates at a rate of3.0 m/s2. How fast is it moving after travelling for 54 meters?​

Answer»

\underline{\underline{\purple{\sf \blue{\mapsto} Step\:\:by\:\:step\: Explanation:}}}

•As per the DATA in Question,

  • Initial velocity of car = 8m/s (u)
  • Final velocity of car = ? (v) .
  • Acceleration of the car = 3.0m/s².
  • Distance travelled by the car = 54M .

•Using the third equation of MOTION :

\boxed{\red{\bf\purple{\dag}\:\:2as\:=\:v^2\:-\:u^2}}

Substituting the RESPECTIVE VALUES ,

\sf{⇒ 2as = v² - u² }

\sf{⇒  2 × 3 × 54 = v² - 8² }

\sf{⇒  324 + 64 = v² }

\sf{⇒ v² = 388}

\sf{⇒ v =} \sqrt{388 }

\sf{⇒ v = 19.69 m/s ≈ 20m/s }

Hence the required answer is\sf{ 19.69 m/s.}

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