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A car moving at 72km/h is stopped in 5 seconds.If it retards uniformly find the distance travelled by the car before it stops.Also find its retardation.plzz answer correctlyit's much important |
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Solution➟ Initial velocity = 72km/h ➟ u = 72 × 5/18 ➟ u = 20m/s ★According first equation of motion★ ➟ v = u + at➟ 0 = 20 + a × 5 ➟ 5a = - 20 ➟ a = - 20/5 ➟ a = - 4m/s² Note : Minus SHOWS car retarded uniformly. ★According third equation of motion★ ➟ v² = u² + 2as➟ (0)² = (20)² + 2 × (-4) × s ➟ 0 = 400 - 8s ➟ 8s = 400 ➟ s = 400/8 ➟ s = 50m Hence, distance travelled by car i.e 50m Additional Information
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