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A car moving along a straight highway with a speed of 108 km/h, is brought to rest! Within a distance of 100 m. How long does it take for the car to stop |
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Answer» Answer: Explanation: v=u+at 0=30+at. (108km/h=30m/sec) at=-30 now s=ut+1/2at² 100=30t+1/2at² 100=t(30+1/2at) 100=t(30+1/2(-30)) 100=t(30-15)=t(15) t=100/15 sec |
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