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A car moves with a speed of 60km/hr in east and with the same speed fir 30min in south. the displacement of car from initial position is |
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Answer» i guess this is ryt. speed = 60km/hr Time (t1)= 1hr , time(t2)=30min= 30/60= 1/2 hr Distance travelled by a CAR in East DIRECTION(s1)= speed× t1 = 60× 1= 60km Distance travelled by a car in SOUTH direction(s2)= speed× t1 = 60×1/2= 30 km Displacement from intial position(s)= √(s1)²+(s²)²= √ (60)²+(30)² = √3600+900 = √900(4+1) = 30√5 Displacement= 30√5km The displacement of car from INITIAL position is 30√5km_ |
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