1.

A car moves along a straight line whosee equation af motion is given by s=12t+3t^2-2t^3where s=meters & t=seconds. then velocity of the car at start will be

Answer»

ANSWER:

Just differentiate the GIVEN equation

Explanation:

S= 12t + 3t²- 2t³

V= 12 + 6T - 6t²



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