A car moves a car covers distance S1 with velocity V1 and distance S2 with velocity V2 between two cities P and Q its average velocity will be?

A car moves a car covers distance S1 with velocity V1 and distance S2

1.	A car moves a car covers distance S1 with velocity V1 and distance S2 with velocity V2 between two cities P and Q its average velocity will be?
Answer» A CAR covers distance s1 with velocity v1 and distance s2 with velocity v2 between two CITIES P and Q.To find :The AVERAGE velocity.Solution :Instantaneous speed of an object is equal to distance travelled per unit time by that object.So,(equation 1)wheres = Distance travelled andt = Time taken.For distance s1,velocity of car = v1,So, By equation 1,(equation 2)So, for covering distance s1, time taken:For covering distance s2, time taken:Average velocity of an object is equal to the ratio of TOTAL displacement travelled and total time taken.As,Total distance travelled in this journey = s1 + s2Total time taken in this journey = T1 + t2,So,Putting the values of time t1 and t2,we getAverage velocity :

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A car moves a car covers distance S1 with velocity V1 and distance S2 with velocity V2 between two cities P and Q its average velocity will be?​

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A car moves a car covers distance S1 with velocity V1 and distance S2 with velocity V2 between two cities P and Q its average velocity will be?