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a car is travelling on a circular road of 500m.at some instant its speed is 50ms and is increasing at a rate of 2ms .its accelration will be: |
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Answer» mple… observe the question, the question states “rate of velocity=2 m/s” i.e. accelaration in tangential direction which is now =2 m/s^2.Now since a body in circular path has two COMPONENTS of accelaration i.e. RADIAL (towards centre) and tangential. We already have the tangential.For the radial accelaration:A(r) = V^2÷R = 30^2÷500 = 900÷500 = 1.8 rad/sec^2.Since these two VECTORS have an angle of 90° b/w them, the NET Vectorial accelaration becomes:(A(t)^2 +A(r)^2)^1÷2 (because cos 90°=0)=√7.24 ≈ 2.7 m/s^2 |
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