1.

A car is travelling at a speed of 21 m/s1. It accelerates at an average rate of 3 m/s2 for a time of 4 seconds. Find the distance it travels during the 4 seconds?

Answer»

[ s = distance , U = initial velocity , t = time , a = acceleration ] s = ut + 1/2 at^2. ( equation : 2nd law of motion )s = 21m/s * 4S + 1/2*3m/s^2*(4s)^2S = 84m + 1/2 * 3m/s^2* 16s^2s = 84m + 12MS = 96mhope it helps you



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