A car is moving with a velocity of 16m/s when beakrs are applied. the

1.	A car is moving with a velocity of 16m/s when beakrs are applied. the force applied by the brake is 1000n .the mass of the car alogn with its passengers is 1200kg how long should the brakes be applied
Answer» Answer: EXPLANATION: given that, Vi=16 m/s and to stop the car final velocity should be zero therefore Vf=0, and we have stopping force F= -1000 N (SINCE, force being acted OPPOSITE the speed of the car) Total mass of the car, m=1200 Kg therefore by Newtons' second law *net force= mass acceleration, and acceleration, a=(Vf-Vi)/t,** so -1000 = 1200(0-16)/t -1000 = 1200(-16)/t 1000 = 120016/t 1000t = 120016 t = (120016)/1000 t=192/10 t = 19.2 seconds The brake should be APPLIED for 19.2 seconds in order to stop the car. have a good day

A car is moving with a velocity of 16m/s when beakrs are applied. the force applied by the brake is 1000n .the mass of the car alogn with its passengers is 1200kg how long should the brakes be applied

Answer»

Answer:

EXPLANATION:

given that, Vi=16 m/s

and to stop the car final velocity should be zero therefore Vf=0,

and we have stopping force F= -1000 N (SINCE, force being acted OPPOSITE the speed of the car)

Total mass of the car, m=1200 Kg

therefore by Newtons' second law

net force= mass * acceleration, and acceleration, a=(Vf-Vi)/t, so

-1000 = 1200*(0-16)/t

-1000 = 1200*(-16)/t

1000 = 1200*16/t

1000*t = 1200*16

t = (1200*16)/1000

t=192/10

t = 19.2 seconds

The brake should be APPLIED for 19.2 seconds in order to stop the car.

have a good day