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A car is moving uniformly along a circle orf raidus `25Csqrt(3)` meter with a time period of 20seconds. A stone is thrown from the car such that it again lands on the car when the car is at a diametricaly opposite point in the orbit. The angle of projection of the stone as seen from the ground should be: (Take `g=10m//s^(2)`) A. `45^(@)`B. `60^(@)`C. `30^(@)`D. none of these |
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Answer» Let T be the time of flight and u be the initial velocity of the stone then: `2R=(u^(2)sin 2 theta)/(g)` . … (i) and `T=(2u sin theta)/(g)` … .(ii) eliminating u, we get `tan theta=(gT^(2))/(4R)=(10xx10^(2))/(4xx250sqrt(3))=(1)/sqrt(3)` `rArr theta=30^(@)` |
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