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A car is moving at a velocity of 54 km/h ^-1 . Suddenly brakes are produced a declaration of 6m/^2 , find the distance covered by the car before coming to rest ?Pls answer fast |
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Answer» U = 54 km/h= 54× 1000/3600= 15 m/s v= u + at 0= 15 + 6.t 6.t = -15 t = -15/6= -5/2 So distance covered in 5/2 seconds S = ut + 1/2 at² = 15× 5/2 + 1/2 × 6 × 25/4 = 75/2 + 75/4 = (75× 3)/ 4 =225/ 4 = 56.25 m |
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