A car is moving at a speed of 72 km/hr. If the wheels of diameter 0.5 m are stopped in 20 rotations by applying the brakes, angular retardation produced by the brake is :5.5 rad/s2 (B) 33.5 rad/s2(C) 29.5 rad/s2 (D) 25.5 rad/s2

A car is moving at a speed of 72 km/hr. If the wheels of diameter 0.5

1.	A car is moving at a speed of 72 km/hr. If the wheels of diameter 0.5 m are stopped in 20 rotations by applying the brakes, angular retardation produced by the brake is :5.5 rad/s2 (B) 33.5 rad/s2(C) 29.5 rad/s2 (D) 25.5 rad/s2
Answer» Here: SPEED of car = 72 km/hr =72×518=20cm/sDiameter of each wheel=0.52mNumber of ROTATION = 20The relation for angular speed is ω=υr=200.25=80 rad/secAngular displacement Q=2π×20=40 π radThe relation for angular retardation is GIVEN byω2=ω20+2aQ 0=(80)2+2a(40π) Or a=(80)280π=−25.5rad/s2

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A car is moving at a speed of 72 km/hr. If the wheels of diameter 0.5 m are stopped in 20 rotations by applying the brakes, angular retardation produced by the brake is :5.5 rad/s2 (B) 33.5 rad/s2(C) 29.5 rad/s2 (D) 25.5 rad/s2​

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A car is moving at a speed of 72 km/hr. If the wheels of diameter 0.5 m are stopped in 20 rotations by applying the brakes, angular retardation produced by the brake is :5.5 rad/s2 (B) 33.5 rad/s2(C) 29.5 rad/s2 (D) 25.5 rad/s2