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A car is moving along a stight horizontal road with a speed `v_(0)` . If the coefficient of friction between the tyres and the road is mu, the shortest distance in which the car can be stopped is.A. `(v_(0)^(2))/( 2mu g)`B. `(v_(0))/( mu g)`C. `((v_(0))/(mu g))^(2)`D. `(v_(0))/(mu)` |
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Answer» Correct Answer - A `0 = v_(0)^(2) - 2mu gs rArr s = (v_(0)^(2))/( 2mu g)` |
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