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A car is driven from 0-s if the car travelling initially with 36 km -h-1 is stopped by the driver after observing a signal by deceleration of 5 m-s-2 the total distance travelled by the car before coming to rest is A) 18 m B) 14m C) 12m D) 10m |
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Answer» Provided that: Initial velocity = 36 kmphFinal velocity = 0 mpsAcceleration = -5 mps sq. Don't be confused!→ Final velocity cames as zero because it is given that the DRIVER stopped the car. → Acceleration cames in negative because it is given that the car is retarding or it decelerates. And we also know that deceleration is the inverse of acceleration. To calculate:The distanceSolution: The DISTANCE = 10 m USING concepts: Formula to CONVERT kmph-mps.Third equation of motion.Using formulas: REQUIRED solution: ~ Firstly let us convert initial velocity into metre per second!Final velocity = 0 mpsInitial velocity = 10 mps~ Now let's calculate the distance by using third equation of motion! |
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