1.

a car is accelerating uniformly from 36km/h in 10 seconds . find a)the acceleration b) the distance travelled by the car during this time interval ?

Answer» ACCELERATION =
\frac{change \: in \: <klux>VELOCITY</klux>}{time \: taken}
change=final velocity -INITIAL velocity
=36km/h=10m/s

acceleration =
\frac{10m {s}^{ - 1} }{10s}  \\  = 1m {s}^{ - 2}
distance=speed×time
=10m/s×10s=100m



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