A car going at a speed of 7 m/s can be stopped by applying brakes in a shortest distance of 10 m. Show that the total frictional force opposing the motion when brakes are applied is 1/4th of the weight of the car(g =9.8 m/s²

A car going at a speed of 7 m/s can be stopped by applying brakes in a

1.	A car going at a speed of 7 m/s can be stopped by applying brakes in a shortest distance of 10 m. Show that the total frictional force opposing the motion when brakes are applied is 1/4th of the weight of the car(g =9.8 m/s²
Answer» For the motor CAR; u = 7 m/s; V = 0; s = 10 m. Using, V2 = u2 + 2as, we get a=v2-u2/2s=o-49/20=-2.45m/sec2If we consider, g = 9.8 m/s2, then we geta=-g/4Thus, the resistance to the motion, that is resistive FORCE is-F=-ma=mg/4This is one FOURTH the weight of the car.mark me as a brainliest if you like my work

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A car going at a speed of 7 m/s can be stopped by applying brakes in a shortest distance of 10 m. Show that the total frictional force opposing the motion when brakes are applied is 1/4th of the weight of the car(g =9.8 m/s²

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