1.

a car falls off a ledge and drops to the ground in 0.9s. if the value of gravitational is 10m/s2,then the speed striking the ground is​

Answer»

Given :-

  • Initial velocity, u = 0 m/s
  • TIME taken, t = 0.9s
  • Acceleration due to gravity, g = 10 m/s²

To find :-

  • Final velocity - v

Solution :-

  • u = 0 m/s
  • t = 0.9s
  • g = 10 m/s²

Substituting the value in 1st equation of motion :-

\sf v = u + at

\sf v = 0 + 0.9 \times 10

\sf v = 9 m/s

Velocity with which it STRIKES the GROUND is 9 m/s.



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