A car can finish a certain journey in 10 hours at a speed of 48 km per

1.	A car can finish a certain journey in 10 hours at a speed of 48 km per hour in order to cover the same distance in 8 hour he speed of the car mustincreased by
Answer» Answer: $\tt\implies \: \boxed{ \red{ \bf \: speed \: is \: 60 \: km \: per \: hour}}$ Step-by-step explanation: ☆ Let the speed of car be X km/ hour. $\begin{gathered}\boxed{\begin{array}{c\|c} \bf speed \: of \: car (km \: per \: hr)& \bf <klux>TIME</klux> \: taken \: in \: hrs \\ \frac{\qquad \qquad\qquad\qquad}{} & \frac{\qquad \qquad\qquad\qquad}{} \\ \sf 48 & \sf 10 \\ \\ \sf x & \sf 8 \\ \\ \sf & \sf \end{array}} \\ \end{gathered}$ ☆ SINCE,more speed, less time taken. ☆ So, it is INVERSE variation. $\tt\implies \:48 \times 10 = x\times 8$ $\tt\implies \: \boxed{ \purple{ \bf \: x = 60 \: km \: per \: hour}}$

A car can finish a certain journey in 10 hours at a speed of 48 km per hour in order to cover the same distance in 8 hour he speed of the car mustincreased by

Answer»

Answer:

$\tt\implies \: \boxed{ \red{ \bf \: speed \: is \: 60 \: km \: per \: hour}}$

Step-by-step explanation:

☆ Let the speed of car be X km/ hour.

$\begin{gathered}\boxed{\begin{array}{c|c} \bf speed \: of \: car (km \: per \: hr)& \bf <klux>TIME</klux> \: taken \: in \: hrs \\ \frac{\qquad \qquad\qquad\qquad}{} & \frac{\qquad \qquad\qquad\qquad}{} \\ \sf 48 & \sf 10 \\ \\ \sf x & \sf 8 \\ \\ \sf & \sf \end{array}} \\ \end{gathered}$