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A car battery of 12 v is connected in series with resistor of 0.1 ohm , 0.2 ohm , 0.2 ohm , 0.4 ohm and 6 ohm. How much current would flow through 6 ohm resistor |
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Answer» Explanation:SINCE all RESISTANCES are connected in series then Rnet=0.1+0.2+0.2+0.4+6=6.9ohmI =V/Rnet =120/69 =1.7391ohmsTherefore that same CURRENT will SLOW through entire circuit and in EVERY resistance |
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