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A car acquires a velocity of 72 km/h in 10s starting from rest. Find (a) accleration (b) distance travelled (c) average velocity |
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Answer» Explanation:Given that:-Initial velocity (u) = 0Final velocity = 72km/h= 20m/sTime TAKEN (t) = 10sa) acceleration =(v-u)/t=(20-0)/10= 2m/s^2b) average velocity = (v+u)/2=(20+0)/2=20/2=10m/sc) let distance be sUsing second equation of motion =ut+(1/2)at^2= (0)(10)+(1/2)(2)(10)^2= 0+100= 100So, the distance covered by the body was 100m.please mark my ANSWER as the brainliest |
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