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A car acquires a velocity of 36 Km/h in 10s starting from rest . Calculate :(i) the acceleration.(ii) the average velocity and (iii) the distance travelled in this time. |
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Answer» →Initial velocity of the car = 0(as it starts from rest)→Final velocity of the car = 36km/h→Time TAKEN = 10sTo find:-Firstly, let's convert the final velocity of the car from km/h to m/s.=>1km/h = 5/18m/s=>36km/h = 5/18×36=>10m/sBy using the 1st equation of motion,we get:-=>v = u+at=>a = v-u/t=>a = 10-0/10=>a = 1m/s²When a body is moving with uniform ACCELERATION,then average velocity of the body is:-=>Vₐᵥ = u+v/2=>Vₐᵥ = 0+10/2=>Vₐᵥ = 5m/sNow,by using the 2nd equation of motion,we get:-=>s = ut+1/2at²=>s = 0(t) + 1/2×1×(10)²=>s = 0.5(100)=>s = 50mThus:-→Acceleration of the car is 1m/s².→Average velocity of the car is 5m/s.→Distance travelled by the car is 50M. |
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