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A car accelerates uniformly from 18Km/h to 36Km/hr in 3 seconds. Calculate the acceleration and the distance covered by the car at that time |
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Answer» u=18km/h 18×5/18 =5m/s v=36km/h 36×5/18 =10m/s t=3second acceleration=10-5/3=5/3 distance=36-18=18km |
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