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A car accelerates uniformly from 18 kilometre per hour to 36 kilometre per hour in 5 seconds calculate the acceleration and the distance covered by the car in 10 secondsPlease explain it thoroughly.... |
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Answer» Explanation: Given parameters Time taken (t) = 5 sec Initial velocity (u) =18 km/hour
u=18×100060×60s
u = 5 m/s Final velocity (v) =36km/hour
v=36×100060×60s
v =10 m/s We need to calculate acceleration and DISTANCE traveled We know that acceleration a = (v – u)/t Substituting the given values in the above equation we get, a = (10 – 5)/5 a =5/5 a = 1 m/s2 We know that distance travelled is CALCULATED by the formula Distance travelled S = u t + (1/2) a × t2 Substituting the given values in the above equation we get, S = 5 × 5 + (1/2) × 1 × 52 S = 25 + (1/2) × 25 S = 25 + 12.5 S = 37.5 m Hence acceleration a =1 m/s2 Distance travelled S =37.5 m |
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