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A capillary tube whose inside radius is `0.5mm` is dipped in water having surface tension `7.0xx10^(-2) N//m`. To what height is the water raised above the normal water level? Angle of contact of water with glass is `0^(@)`. Density of water is `10^(3)kg//m^(3) and g=9.8 m//s^(2)`. |
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Answer» Correct Answer - B::C `h=(2T costheta)/(r rho g)` Substituting the proper values, we have `h =((2)(7.0xx10^(-2))cos 0^(@))/((0.5 xx 10^(-3)) (10^(-3)) (9.8))` `=2.86xx10^(-2)m=2.86cm`. |
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