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A capacitor of capacitance 200 micro farad is charged to a potential of 1000w. The stored energy in wattsecond is |
| Answer» CHARGED capacitor is connected with ANOTHER uncharged capacitor , then charge transfer from charged capacitor to uncharged capacitor untill both attend same potential .now, A capacitor of CAPACITANCE 200 PF charged by 300V battery Means charge on this capacitor = CV = 200 × 300 pC = 6 × 10⁴ pC Now, charged capacitor of charge 6 × 10⁴ pC is connected with uncharged capacitor . Let final potential of both capacitors is V Then, intial charge = final charge 6 × 10⁴ pC = 200 × V + 100 × VV = 200 V Hence, final potential is 200V Now, energy stored intially on capacitor of 200pF = 1/2 CV² = 1/2 × (200pF)×( 300V )²= 100 × 10⁻¹² × 90000 J= 9 × 10⁻⁶ JFinally energy stored in both capacitors = 1/2(C + C')V²= 1/2 × (200pF + 100pF) × (200V)²= 150 × 10⁻¹² × 40000= 6 × 10⁻⁶ J Hence, difference in energy stored = intial energy - final energy = 9 × 10⁻⁶ J - 6 × 10⁻⁶ J = 3 × 10⁻⁶JRead more on Brainly.in - brainly.in/question/2753317#readmore | |