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A capacitor of capacitance `0.5 mu F` is discharged through a resistance. Find the value of resistance if half the charge on capacitor escapes in one minute. |
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Answer» Hene, `C 0.5 mu F = 0.5 xx 10^(-6) F, R = ?` `q = (q_(0))/(2), t = 1 min. = 60 sec`. As `q = q_(0) e^(-t//RC) :. (q_(0))/(2) = q_(0) e^(-60 // RC)` `log_(e) 1 - log_(e) 2 = - (60)/(RC) log_(e) e` `0 - 2.303 log_(10) 2 = - (60)/(RC) xx 1` `2.303 xx 0.3010 = (60)/(R(0.5 xx 10^(-6)))` `:. R = (60)/(0.5 xx 10^(-6) xx 2.303 xx 0.3010)` ` = 1.73 xx 10^(8) ohm` |
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