1.

A capacitor having a capacitance of 100muFis charged to a potential difference of 24 V. The charging battery is disconnected and the capacitor is connected to another battery of emf 12 V with the positive plate of the capacitor joined with the positive terminal of the battery. Find the decrease in electrostatic field energy .

Answer»

11.6 mJ
21.6 mJ
31.6 mJ
41.6 mJ

Answer :B


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