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A Capacitor blocks d.c. and allows a.c. Why ? |
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Answer» The capacitative reactance is `X_(C ) = (1)/(omega C) = (1)/(2 pi v C)` For d.c., `v = 0 , :. X_(C ) = oo` i.e., capacitor offers infinite resistance to d.c. and hence block it. For a.c., `v != 0`, `:. X_(C ) != oo`, but it has only a finite value Therefore, a.c. can pass through the capacitor. |
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