A candidate who gets 36%,another candidate, who gets 43% narks, gets 18 more marks than thenarks in the examination fails by 24 marks butinimum pass marks. Find the maximum marks and the percentage of passmarks.

A candidate who gets 36%,another candidate, who gets 43% narks, gets 1

1.	A candidate who gets 36%,another candidate, who gets 43% narks, gets 18 more marks than thenarks in the examination fails by 24 marks butinimum pass marks. Find the maximum marks and the percentage of passmarks.
Answer» First candidate = 36% × x + 24Second candidate = 43% × x - 18First candidate = Second candidate36/100 × x + 24 = 43/100 × x - 189x/25 + 24 = 43x/100 - 189x/25 - 43x/100 = -24 - 1836x/100 - 43x/100 = -4236x - 43x/100 = -42-7x/100 = -42x = -42 × -100/7x = 600Maximum marks = 60036% × x + 24 = y36/100 × 600 + 24 = y216 + 24 = y240 = yPassing marks = 240