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A candidate scored 25% marks in an examination and failed by 30 marks, while another candidate whoscored 50% marks got 20 marks more than the minimum pass marks. Find the maximum marks andminimum pass marks. |
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Answer» Step-by-step EXPLANATION: Solution:- Minimum marks to pass =25% of x+30=4x+30 Now according to question, 4x+30=2x−20 2x−4x=30+20 ⇒x=50×4=200 Hence the maximum marks to be obtained are 200. Now, minimum passing marks =4200+30=80 Hence the maximum marks to be obtained are 200 and the minimum passing marks are 80. |
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