A can do apiece of work in 24 days. B is 60% more efficient thanA. The

1.	A can do apiece of work in 24 days. B is 60% more efficient thanA. The no. of days B to do the same piece of work is
Answer» Answer: We KNOW that B is 60% more efficient than A. So, the amount of WORK done by B in one day can be CALCULATED as follows, Work done by B in 1 day =124+60100×124=10240+6240=16240=115. Step-by-step explanation: A's 1 day's work = 24 1 B's 1 day's work = 24 1 +60Percentof 24 1 = 24 1 × 100 160 = 15 1 ∴BCandosameworkin15days ∴Bcandodoubleworkin2×15=30days

A can do apiece of work in 24 days. B is 60% more efficient thanA. The no. of days B to do the same piece of work is

Answer»

Answer:

We KNOW that B is 60% more efficient than A. So, the amount of WORK done by B in one day can be CALCULATED as follows, Work done by B in 1 day =124+60100×124=10240+6240=16240=115.

Step-by-step explanation:

A's 1 day's work =

B's 1 day's work =

+60Percentof

100

160

∴BCandosameworkin15days

∴Bcandodoubleworkin2×15=30days

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A can do apiece of work in 24 days. B is 60% more efficient thanA. The no. of days B to do the same piece of work is​

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A can do apiece of work in 24 days. B is 60% more efficient thanA. The no. of days B to do the same piece of work is