A can do a piece of work in 24 days. If B is 60% more efficient than A

1.	A can do a piece of work in 24 days. If B is 60% more efficient than A how many days are required by B to do the twice as long as the earlier work is.
Answer» Answer: We know that B is 60% more efficient than A. So, the amount of work done by B in one day can be calculated as FOLLOWS, Work done by B in 1 day =124+60100×124=10240+6240=16240=115. THEREFORE, the number of days required by B to complete the same QUANTITY of work as A is 15 days.

A can do a piece of work in 24 days. If B is 60% more efficient than A how many days are required by B to do the twice as long as the earlier work is.

Answer»

Answer:

We know that B is 60% more efficient than A. So, the amount of work done by B in one day can be calculated as FOLLOWS, Work done by B in 1 day =124+60100×124=10240+6240=16240=115. THEREFORE, the number of days required by B to complete the same QUANTITY of work as A is 15 days.

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A can do a piece of work in 24 days. If B is 60% more efficient than A how many days are required by B to do the twice as long as the earlier work is.​

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A can do a piece of work in 24 days. If B is 60% more efficient than A how many days are required by B to do the twice as long as the earlier work is.