A can do a piece of work in 15 days. B is 25% more efficient than A an

1.	A can do a piece of work in 15 days. B is 25% more efficient than A and C is 40% more efficient than B. A and C work together for 3 days and then C leaves. A and B together will compete the remaining work in:1. \(2\frac{1}{2}\) days2. \(3\frac{1}{2}\) days3. 4 days4. 3 days
Answer» Correct Answer - Option 4 : 3 days Given :- A can do a piece of work in 15 days B is 25% more efficient than A and C is 40% more efficient than B Concept :- Ratio of efficiency is reciprocal of time. Number of days required to complete a certain work = (Work to be completed/Work efficiency) Calculation :- Let efficiency of A be 100 ⇒ Efficiency of B = 100 + (100 × 25%) ⇒ Efficiency of B = 100 + 25 = 125 ⇒ Efficiency of C = 125 + (125 × 40%) ⇒ Efficiency of C = 125 + 50 = 175 ⇒ Ratio of efficiency of A ∶ B ∶ C = 100 ∶ 125 ∶ 175 ⇒ Ratio of efficiency of A ∶ B ∶ C = 4 ∶ 5 ∶ 7 A work for 15 days with efficiency 4 ⇒ Total work done by A = 15 × 4 = 60 unit Now, (A + C) together work for 3 days. ⇒ Total efficiency of A and C together = 4 + 7 = 11 unit/day ⇒ Total work done by A and C together = 11 × 3 = 33 unit ⇒ Remaining work = Total work - Work done by A and C together ⇒ Remaining work = 60 - 33 ⇒ Remaining work = 27 unit ⇒ Total efficiency of A and B together = 4 + 5 = 9 unit/day ⇒ Required number of days = (27/9) = 3 days ⇒ Time required to complete remaining work = 3 days. ∴ Time required to complete remaining work is 3 days.

A can do a piece of work in 15 days. B is 25% more efficient than A and C is 40% more efficient than B. A and C work together for 3 days and then C leaves. A and B together will compete the remaining work in:1. \(2\frac{1}{2}\) days2. \(3\frac{1}{2}\) days3. 4 days4. 3 days

Answer» Correct Answer - Option 4 : 3 days

Given :-

A can do a piece of work in 15 days

B is 25% more efficient than A and

C is 40% more efficient than B

Concept :-

Ratio of efficiency is reciprocal of time.

Number of days required to complete a certain work = (Work to be completed/Work efficiency)

Calculation :-

Let efficiency of A be 100

⇒ Efficiency of B = 100 + (100 × 25%)

⇒ Efficiency of B = 100 + 25 = 125

⇒ Efficiency of C = 125 + (125 × 40%)

⇒ Efficiency of C = 125 + 50 = 175

⇒ Ratio of efficiency of A ∶ B ∶ C = 100 ∶ 125 ∶ 175

⇒ Ratio of efficiency of A ∶ B ∶ C = 4 ∶ 5 ∶ 7

A work for 15 days with efficiency 4

⇒ Total work done by A = 15 × 4 = 60 unit

Now,

(A + C) together work for 3 days.

⇒ Total efficiency of A and C together = 4 + 7 = 11 unit/day

⇒ Total work done by A and C together = 11 × 3 = 33 unit

⇒ Remaining work = Total work - Work done by A and C together

⇒ Remaining work = 60 - 33

⇒ Remaining work = 27 unit

⇒ Total efficiency of A and B together = 4 + 5 = 9 unit/day

⇒ Required number of days = (27/9) = 3 days

⇒ Time required to complete remaining work = 3 days.

∴ Time required to complete remaining work is 3 days.