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A can do a piece of work in 12 days and B in 15 days. They work together for 5 days and then B left. The number of days taken by A to finish twice the remaining work is1. 32. 83. 64. 7 |
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Answer» Correct Answer - Option 3 : 6 Given: A can do a piece of work in 12 days and B in 15 days. Calculations: Time taken by A to complete the work = 12 days so part of work done in 1 day = 1/12 similarly, part of work done by B in 1 day = 1/15 work done by (A + B) in 1 day = (1/12 + 1/15) = 9/60 = 3/20 so work done by (A + B) in 5 day = 15/20 = 3/4 Remaining work = 1 - 3/4 = 1/4 Time taken by A to complete the remaining work = 12/4 = 3 days Time taken by A to complete twice the remaining work = 6 days ∴ the correct answer is 6 days. |
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