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A Can Contains A Mixture Of Two Liquids A And B In The Ratio 7: 5. When 9 Litres Of Mixture Are Drawn Off And The Can Is Filled With B, The Ratio Of A And B Becomes 7: 9. How Many Litres Of Liquid A Were Contained By The Can Initially? |
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Answer» Suppose the can initially CONTAINS 7x and 5x litres of MIXTURES A and B respectively QUANTITY of An in mixture left = (7x - 7/12 x 9) litres = (7x - 21/4) litres. Quantity of B in mixture left = (5x - 5/12 x 9) litres = (5x - 15/4) litres. (7x - 21/4) / [(5x - 15/4) +9] = 7/9 = › 28x - 21/20x + 21 = 7/9 =› 252x - 189 = 140x + 147 =› 112x = 336 =’ x = 3. So, the can contained 21 litres of A. Suppose the can initially contains 7x and 5x litres of mixtures A and B respectively Quantity of An in mixture left = (7x - 7/12 x 9) litres = (7x - 21/4) litres. Quantity of B in mixture left = (5x - 5/12 x 9) litres = (5x - 15/4) litres. (7x - 21/4) / [(5x - 15/4) +9] = 7/9 = › 28x - 21/20x + 21 = 7/9 =› 252x - 189 = 140x + 147 =› 112x = 336 =’ x = 3. So, the can contained 21 litres of A. |
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