A can complete a work in a timedouble than B and triple than C. If thr

1.	A can complete a work in a timedouble than B and triple than C. If three tegether cancomplete the work in 20 days then in how many dayseach can complete the work separately?
Answer» Let A can complete work in 6n daysThen B can complete work 3n daysC can complete work in 2n days A's one day work = 1/6nB's one day work = 1/3nC's one day work = 1/2n (A+B+C)'s one day work = 1/20 Hence,1/6n + 1/3n + 1/2n = 1/20(1 + 2 + 3)/6n = 1/201/n = 1/20n = 20 Therefore,A can complete work in 6n = 620 = 120 daysB can complete work in 3n = 320 = 60 daysC can complete work in 2n = 40 days.

A can complete a work in a timedouble than B and triple than C. If three tegether cancomplete the work in 20 days then in how many dayseach can complete the work separately?

Answer»

Let A can complete work in 6n daysThen B can complete work 3n daysC can complete work in 2n days

A's one day work = 1/6nB's one day work = 1/3nC's one day work = 1/2n

(A+B+C)'s one day work = 1/20

Hence,1/6n + 1/3n + 1/2n = 1/20(1 + 2 + 3)/6n = 1/201/n = 1/20n = 20

Therefore,A can complete work in 6n = 6*20 = 120 daysB can complete work in 3n = 3*20 = 60 daysC can complete work in 2n = 40 days.