(a) Calculate \( \Delta \) Go for the reaction an \( Zn ( s )+ Cu ^{2+

1.	(a) Calculate \( \Delta \) Go for the reaction an \( Zn ( s )+ Cu ^{2+}( aq ) \longrightarrow Zn ^{2+}( aq )+ Cu ( s ) \) Given : \( E ^{\circ} \) for \( Zn ^{2+} / Zn =-0.76 V \) and \( E ^{\circ} \) for \( Cu ^{2+} / Cu =+0.34 V \) \( R =8.314 JK ^{-1} mol ^{-1} \) \( F =96500 C mol ^{-1} \). (b) Give two advantages of fuel cells.
Answer» We have given, \(E^\circ_{Zn^{+2}/Zn}\) = -0.76 V \(E^\circ_{Cu^{+2}/Cu}\) = + 0.34 V Zn⁺² + 2e^- \(\longrightarrow\) Zn, \(E^\circ_1\) = 0.76 V---(1) Cu⁺² + 2e^- \(\longrightarrow\) Cu, \(E^\circ_2\) = +0.34 V---(2) (2) - (1) we get Zn + Cu⁺² \(\longrightarrow\) Cu + Zn⁺² E^o = \(E^\circ_2-E_1\) E^o = 0.34 - (-0.76) E^o = 1.10 V As we know, Δ G^o = -nFE^o where, n = Number of transfered electrons F = Faraday constant 96500 C mol^-1 E^o = standard electrode potential \(\therefore\) Δ G^o = -2 x 96500 x 1.10 = 212.3 KJ Advantage of fuel cell- * Fuel cells have 0 higher efficiency than diesel or gas engines. * Fuel cells can eliminate pollution caused by burning fossil fuels. * The maintenance of fuel cells is simple.

(a) Calculate \( \Delta \) Go for the reaction an \( Zn ( s )+ Cu ^{2+}( aq ) \longrightarrow Zn ^{2+}( aq )+ Cu ( s ) \) Given : \( E ^{\circ} \) for \( Zn ^{2+} / Zn =-0.76 V \) and \( E ^{\circ} \) for \( Cu ^{2+} / Cu =+0.34 V \) \( R =8.314 JK ^{-1} mol ^{-1} \) \( F =96500 C mol ^{-1} \). (b) Give two advantages of fuel cells.

Answer»

We have given,

\(E^\circ_{Zn^{+2}/Zn}\) = -0.76 V

\(E^\circ_{Cu^{+2}/Cu}\) = + 0.34 V

Zn⁺² + 2e^- \(\longrightarrow\) Zn, \(E^\circ_1\) = 0.76 V---(1)

Cu⁺² + 2e^- \(\longrightarrow\) Cu, \(E^\circ_2\) = +0.34 V---(2)

(2) - (1) we get

Zn + Cu⁺² \(\longrightarrow\) Cu + Zn⁺²

E^o = \(E^\circ_2-E_1\)

E^o = 0.34 - (-0.76)

E^o = 1.10 V

As we know,

Δ G^o = -nFE^o

where,

n = Number of transfered electrons

F = Faraday constant 96500 C mol^-1

E^o = standard electrode potential

\(\therefore\) Δ G^o = -2 x 96500 x 1.10

= 212.3 KJ

Advantage of fuel cell-

* Fuel cells have 0 higher efficiency than diesel or gas engines.

* Fuel cells can eliminate pollution caused by burning fossil fuels.

* The maintenance of fuel cells is simple.