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A cable car used for carrying materials in a hydroelectric project is at rest on a track formed at an angle of 30° with the vertical. The gross weight of the car and its load is 60 kN and its centroid is at a point 800 mm from the track half way between the axles. The car is held by a cable as shown in Fig. The axles of the car are at a distance 1.2 m. Find the tension in the cables and reaction at each of the axles neglecting friction of the track. |
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Answer» Let T be the tension in the cable and the reaction at the pair of wheels be R1 and R2 as shown in Fig. Now, ∑ of forces parallel to the track = 0, gives T – 60 sin 60° = 0 T = 51.9615 kN. Taking moment equilibrium condition about upper axle point on track, we get R1 × 1200 + T × 600 – 60 sin 60° × 800 – 60 cos 60° × 600 = 0 R1 = 23.6603 kN. ∑ of forces normal to the plane = 0, gives R1 + R2 – 60 cos 60° = 0 R2 = 30 – 23.6603 R2 = 6.3397 kN. |
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