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= a +by 22 +4 = 2 solve by crossmultiplication method |
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Answer» Given (x/a) + (y/b) = a + bMultiply by (1/a) both sides, we get(x/a^2) + (y/ab) = 1 + (b/a) → (1)Given other linear equation as (x/a2) + (y/b^2) = 2 → (2)Subtract (2) from (1), we get(x/a^2) + (y/ab) = 1 + (b/a)(x/a^2) + (y/b^2) = 2----------------------------------(y/ab) − (y/b2) = (b/a) − 1⇒ y[(b − a)/ab^2] = (b − a)/a∴ y = b^2Puty = b^2in (x/a^2) + (y/b^2) = 2⇒ (x/a^2) + (b^2/b^2) = 2⇒ (x/a^2) + 1 = 2⇒ (x/a2) = 1∴ x = a^2 shahs inch she'd KFC fix Hf no problem at all the |
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